25x^2-100x+64=0

Solution for 25x^2-100x+64=0 equation:

25x^2-100x+64=0

a = 25; b = -100; c = +64;
Δ = b2-4ac
Δ = -1002-4·25·64
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-60}{2*25}=\frac{40}{50}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+60}{2*25}=\frac{160}{50}
=3+1/5
$